Question
#include<stdio.h>
int main()
{
char a[] = "Visual C++";
char *b = "Visual C++";
printf("%d, %d\n", sizeof(a), sizeof(b));
printf("%d, %d", sizeof(*a), sizeof(*b));
return 0;
}
A. 10, 2
2, 2
B. 10, 4
1, 2
C. 11, 4
1, 1
D. 12, 2
2, 2
If the size of pointer is 32 bits What will be the output of the program ?
#include<stdio.h>
int main()
{
char a[] = "Visual C++";
char *b = "Visual C++";
printf("%d, %d\n", sizeof(a), sizeof(b));
printf("%d, %d", sizeof(*a), sizeof(*b));
return 0;
}
A. 10, 2
2, 2
B. 10, 4
1, 2
C. 11, 4
1, 1
D. 12, 2
2, 2
Answer: Option B
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Answer: (C)
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