Question
#include<stdio.h>
int main()
{
int i;
char a[] = "\0";
if(printf("%s", a))
printf("The string is empty\n");
else
printf("The string is not empty\n");
return 0;
}
What will be the output of the program ?
#include<stdio.h>
int main()
{
int i;
char a[] = "\0";
if(printf("%s", a))
printf("The string is empty\n");
else
printf("The string is not empty\n");
return 0;
}
Answer: Option B
Was this answer helpful ?
The function printf() returns the number of charecters printed on the console.
Step 1: char a[] = "�"; The variable a is declared as an array of characters and it
initialized with "�". It denotes that the string is empty.
Step 2: if(printf("%s", a)) The printf() statement does not print anything, so it returns
'0'(zero). Hence the if condition is failed.
In the else part it prints "The string is not empty".
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution