Question
What is the product of the roots of the equation $x^2 - √3$ = 0 ?
Answer: Option A
Answer:(b)$x^2 - √3$ = 0$x^2-(3)^{1/2}=0$$x^2-(3^{1/4})^2=0$$(x+3^{1/4})(x-3^{1/4})=0$$x=3^{1/4} or {-3}^{1/4}$Product of roots$=3^{1/4}×-3^{1/4}=-√3$Note : Product of the roots of $ax^2+bx+c=0 is c/a$Product of the roots of $x^2-b. 0-√3=0 is -√3$
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Answer:(b)$x^2 - √3$ = 0$x^2-(3)^{1/2}=0$$x^2-(3^{1/4})^2=0$$(x+3^{1/4})(x-3^{1/4})=0$$x=3^{1/4} or {-3}^{1/4}$Product of roots$=3^{1/4}×-3^{1/4}=-√3$Note : Product of the roots of $ax^2+bx+c=0 is c/a$Product of the roots of $x^2-b. 0-√3=0 is -√3$
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