Question
What is the probability of getting a sum 9 from two throws of a dice?
Answer: Option C
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In two throws of a dice, n(S) = (6 x 6) = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.
So, \(P(E) = \frac{n(E)}{n(S)}=\frac{4}{36}=\frac{1}{9}.\)
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