Question
Three unbiased coins are tossed. What is the probability of getting at most two heads?
Answer: Option D
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Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
So, \(P(E) = \frac{n(E)}{n(S)}=\frac{7}{8}\)
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