Question
In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:
Answer: Option A
Was this answer helpful ?
Let S be the sample space and E be the event of selecting 1 girl and 2 boys.
Then, n(S) = Number ways of selecting 3 students out of 25.
= 25C3 `
= \(\frac{(25\times24\times23)}{(3\times2\times1)}\)
= 2300.
n(E) = (10C1 x 15C2)
= \(\left[10\times\frac{(15\times14)}{(2\times1)}\right]\)
=1050.
So, \(P(E) = \frac{n(E)}{n(S)}=\frac{1050}{2300}=\frac{21}{46}.\)
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution