Question
1.
#include
2.
#include
3.
using namespace std;
4.
int main ()
5.
{
6.
unsigned int i;
7.
deque mydeque;
8.
mydeque.push_back (100);
9.
mydeque.push_back (200);
10.
mydeque.push_back (300);
11.
for(deque :: iterator it = mydeque.begin(); it != mydeque.end(); ++it)
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{
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}
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mydeque.clear();
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mydeque.push_back (110);
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mydeque.push_back (220);
17.
for(deque :: iterator it = mydeque.begin(); it != mydeque.end(); ++it)
18.
cout
What is the output of this program?
1.
#include
2.
#include
3.
using namespace std;
4.
int main ()
5.
{
6.
unsigned int i;
7.
deque mydeque;
8.
mydeque.push_back (100);
9.
mydeque.push_back (200);
10.
mydeque.push_back (300);
11.
for(deque :: iterator it = mydeque.begin(); it != mydeque.end(); ++it)
12.
{
13.
}
14.
mydeque.clear();
15.
mydeque.push_back (110);
16.
mydeque.push_back (220);
17.
for(deque :: iterator it = mydeque.begin(); it != mydeque.end(); ++it)
18.
cout
Answer: Option C
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In this program, We cleared the old values presented in the dequeue with the new values.
Output:
$ g++ seq2.cpp
$ a.out
110 220
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