Question
1.
#include
2.
#include
3.
using namespace std;
4.
int main ()
5.
{
6.
deque mydeque (5);
7.
deque::reverse_iterator rit = mydeque.rbegin();
8.
int i = 0;
9.
for (rit = mydeque.rbegin(); rit!= mydeque.rend(); ++rit)
10.
*rit = ++i;
11.
for (deque :: iterator it = mydeque.begin();
12.
it != mydeque.end(); ++it)
13.
cout
What is the output of this program?
1.
#include
2.
#include
3.
using namespace std;
4.
int main ()
5.
{
6.
deque mydeque (5);
7.
deque::reverse_iterator rit = mydeque.rbegin();
8.
int i = 0;
9.
for (rit = mydeque.rbegin(); rit!= mydeque.rend(); ++rit)
10.
*rit = ++i;
11.
for (deque :: iterator it = mydeque.begin();
12.
it != mydeque.end(); ++it)
13.
cout
Answer: Option C
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In this program, We used the operation of rbegin and rend on dequeue and produced the result.
Output:
$ g++ seq.cpp
$ a.out
5 4 3 2 1
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