Question
Two workers A and B working together completed a job in 5 days . If A worked twice as efficiently as he actually did and B worked `1/3` as efficiently as he actually did , the work would have been completed in 3 days. A alone could complete he work in
Answer: Option B
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Let A's 1 days work = `x` and B's 1days work = y
Then ,`x + y = 1/5 and 2x + 1/3 y = = 1/3`
Solving, we get : `x = 4/25 and y = 1/25`
`:.` A's 1 day's work = 4/25.
So, A alone could complete the work in `25/4 = 6 1/4`days.
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