Question
A is 50% as efficient as B, C dose half of the work done by A and B together . If C alone does the work in 40 days, then A, B and C together can do the work in :
Answer: Option A
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(A's 1 day's work ) : (B's 1 days work) = 150 : 100 = 3 : 2
Let A's and B's 1 day's work be 3`x` and 2`x` respectively.
Then, C's 1 day's work = `((3x + 2x)/(2)) = (5x)/(2)`
`:.` `(5x)/(2) = 1/40 or x = (1/40 xx 2/5) = 1/100`
A's 1 day's work = `3/100` ; B's 1 day's work = `1/50` ; C's 1 day's work = `1/40`
(A + B + C)'s 1 day's work = `(3/100 + 1/50 + 1/40) = 15/200 = 3/40`
So , A, B, and C together can do the work in `40/3` = `13 1/3` days.
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