Question
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
Answer: Option B
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Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
\(\therefore \frac{27x+17y}{x+y}=23\)
\(\Rightarrow27x+17y = 23x+23y\)
4x = 6y
\(\frac{x}{y}= \frac{3}{2}\)
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