Question
Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option C
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Relative speed = (60+ 90) km/hr
=\(\left(150\times\frac{5}{18}\right)m/sec\)
= \(\left(\frac{125}{3}\right)m/sec.\)
Distance covered = (1.10 + 0.9) km = 2 km = 2000 m.
Required time = \(\left(2000\times\frac{3}{125}\right)sec = 48sec.\)
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