Question
Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:
Answer: Option C
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Let the speed of the slower train be x m/sec.
Then, speed of the faster train = 2x m/sec.
Relative speed = (x + 2x) m/sec = 3x m/sec.
\(\left(\frac{100+100}{8}\right) = 3x\)
24x = 200
x=\(\frac{25}{3}.\)
So, speed of the faster train = \(\frac{50}{3}m/sec\)
= \(\left(\frac{50}{3}\times\frac{18}{5}\right)km /hr\)
= 60 km/hr.
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