Question
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Answer: Option C
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Speed of train relative to jogger = (45 - 9) km/hr = 36 km/hr.
=\(\left(36\times\frac{5}{18}\right)m/sec\)
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
thairfor Time taken = \(\left(\frac{360}{10}\right)sec = 36 sec. \)
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