Three resistances each of 4 Ohm are connected in the form of an equilateral tr

Question

Three resistances each of 4 Ohm are connected in the form of an equilateral triangle. The effective resistance between any two corners is:

Options:

A .

\frac{3}{8} O h m

B .

\frac{8}{3} O h m

C .

8 O h m

D .

12 O h m

Answer: Option B
:
B

Two in series = 8 Ohm

This 8 Ohm will be parallel to 4 Ohm which gives a resultant = ( $\frac{4 \times 8}{4 + 8}) = (\frac{8}{3}) O h m$ .

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