Question
There is a number which is formed from 6 natural numbered tiles arranged in a row. The value of the first tile (leftmost) is 1. If this tile is moved from the leftmost place to the rightmost place, then the number obtained is three times of the original number. Then the sum of the digits of this special number is?
Answer: Option D
:
D
Option(d)
3 * (1ABCDE) = ABCDE1
The only possibility for the last digit for the number is 7, which when multiplied by 3 gives 1 with a carry over 2
Proceeding this way,the number can be determined as
E = 7, D = 5, C = 8, B = 2, A = 4. The sum of the digits = 27
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:
D
Option(d)
3 * (1ABCDE) = ABCDE1
The only possibility for the last digit for the number is 7, which when multiplied by 3 gives 1 with a carry over 2
Proceeding this way,the number can be determined as
E = 7, D = 5, C = 8, B = 2, A = 4. The sum of the digits = 27
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