Question
The value of \(\frac{0.1\times0.1\times0.1+0.02\times0.02\times0.02}{0.2\times0.2\times0.2+0.04\times0.04\times0.04} \)
Answer: Option B
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Given expression = \(\frac{(0.1)^{3}+(0.02)^{3}}{2^{3}[(0.1)^{3}+(0.02)^{3}]}=\frac{1}{8}= 0.125\)
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