Question
The roots of the equation (x+1)(x+8) +10 = 0 are given as p and q. Find the roots of (x+p)(x+q)-4=0
Answer: Option C
:
C
Option c (x+1)(x+8)+10 can be expanded as x2+9x+8+10=0 x2+9x+18=0 Sum of roots p+q= -9 Product of roots pq = 18(x+p)(x+q)-4=0 can be written as x2+ (p+q)x+pq-4=0 x2-9x+18-4=0x2-9x+14=0Roots are 7 and 2
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:
C
Option c (x+1)(x+8)+10 can be expanded as x2+9x+8+10=0 x2+9x+18=0 Sum of roots p+q= -9 Product of roots pq = 18(x+p)(x+q)-4=0 can be written as x2+ (p+q)x+pq-4=0 x2-9x+18-4=0x2-9x+14=0Roots are 7 and 2
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