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Question
If a and b are the roots of the equation x2+px+1=0 and ; c and d are the roots of the equation x2+qx+1=0, then (a-c)(b-c)(a+d)(b+d)=? 
Options:
A .  p2-q2
B .  a2+b2
C .  q2-p2
D .  q2+p2
E .  p2
Answer: Option C
:
C
Shortcut: AssumptionOption (c)Product of roots=1 is the only constraint.Assume values that satisfy the constraint and substitute, take a= -1 and b= -1, then p= 2Assume c= - 1/2 and d= - 2; q= 5/2 Question is = (a-c)(b-c)(a+d)(b+d)=9/4Only option (c) satisfies this => q2 –p2 = 25/4 – 4 =9/4

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