Question
The resultant of two vectors A and B is perpendicular to the vector A and its magnitude is equal to half the magnitude of vector B. The angle between A and B is
Answer: Option B
:
B
B2 = √A2+B2+2ABcosθ ..(i)
∴ tan 90∘ = BsinθA+Bcosθ ⇒ A + Bcosθ = 0
∴ cos θ = - AB
Hence, from (i) B24 = A2+B2−2A2 ⇒ A = √3B2
⇒ cos θ = - AB = - √32 ∴ θ = 150∘
Was this answer helpful ?
:
B
B2 = √A2+B2+2ABcosθ ..(i)
∴ tan 90∘ = BsinθA+Bcosθ ⇒ A + Bcosθ = 0
∴ cos θ = - AB
Hence, from (i) B24 = A2+B2−2A2 ⇒ A = √3B2
⇒ cos θ = - AB = - √32 ∴ θ = 150∘
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution