Question
The least perfect square number divisible by 3, 4, 5, 6 and 8 is = ?
Answer: Option D
L.C.M. of 3, 4, 5, 6, 8 is 120
Now 120 = 2 × 2 × 2 × 3 × 5
To make it a perfect square, it must be multiplied by 2 × 3 × 5
So, required number
$$\eqalign{
& = {2^2} \times {2^2} \times {3^2} \times {5^2} \cr
& = 3600 \cr} $$
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L.C.M. of 3, 4, 5, 6, 8 is 120
Now 120 = 2 × 2 × 2 × 3 × 5
To make it a perfect square, it must be multiplied by 2 × 3 × 5
So, required number
$$\eqalign{
& = {2^2} \times {2^2} \times {3^2} \times {5^2} \cr
& = 3600 \cr} $$
Was this answer helpful ?
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