Question
The focal lengths of the objective and eye-lens of a microscope are 1 cm and 5 cm respectively. If the magnifying power for the relaxed eye is 45, then the length of the tube is
Answer: Option C
:
C
Given that f0=1cm,fe=5cm,m∞=45
By using m∞=(L∞−f0−fe)f0fe⇒45=(L∞−1−5)×251×5⇒L∞=15cm
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C
Given that f0=1cm,fe=5cm,m∞=45
By using m∞=(L∞−f0−fe)f0fe⇒45=(L∞−1−5)×251×5⇒L∞=15cm
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