Question
A compound microscope has a magnifying power 30. The focal length of its eye-piece is 5 cm. Assuming the final image to be at the least distance of distinct vision. The magnification produced by the objective will be
Answer: Option B
:
B
Magnification produced by compound microscope m=m0×me
where m0=? and me=(1+Dfe)=1+255=6⇒30=−m0×6⇒m0=−5
Was this answer helpful ?
:
B
Magnification produced by compound microscope m=m0×me
where m0=? and me=(1+Dfe)=1+255=6⇒30=−m0×6⇒m0=−5
Was this answer helpful ?
Latest Videos
Latest Test Papers
Submit Solution