Question
The electron belongs to the angular momentum of an e−in a Bohr's orbit of H atom is 4.2178 × 10−34 Kg.m2.Sec−1.
Answer: Option C
:
C
nh2π=4.2178×10−34
n = 2π×4.2178×10−34h
=2×3.14×4.2178×10−346.625×10−34
n = 4
N-shell
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:
C
nh2π=4.2178×10−34
n = 2π×4.2178×10−34h
=2×3.14×4.2178×10−346.625×10−34
n = 4
N-shell
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