Question
The diameter of the eye-ball of a normal eye is about 2.5 cm. The power of the eye lens varies from
Answer: Option D
:
D
An eye sees distant objects with full relaxation so 12.5×10−2−1−∞=1f or
P=1f=125×10−2=40D
An eye sees an object at 25 cm with strain so 12.5×10−2−1−25×10−2=1forP=1f=40+4=44D
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:
D
An eye sees distant objects with full relaxation so 12.5×10−2−1−∞=1f or
P=1f=125×10−2=40D
An eye sees an object at 25 cm with strain so 12.5×10−2−1−25×10−2=1forP=1f=40+4=44D
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