The bond dissociation energy of C - H in C H 4 from the equation C(g) + 4H(g) ⟶ C H 4 (g) Δ H = -397.8 Kcal is Options: A . &nbsp+99.45 kcal B . &nbsp-99.45 kcal C . &nbsp+397.8 kcal D . &nbsp-397.8 kcal

The bond dissociation energy of C - H in CH4 from the equation C(g) + 4H(g) &#x

Question

The bond dissociation energy of C - H in

C H_{4}

from the equation
C(g) + 4H(g)

⟶

C H_{4}

(g)

Δ

H = -397.8 Kcal is

Options:

A . +99.45 kcal

B . -99.45 kcal

C . +397.8 kcal

D . -397.8 kcal

Answer: Option A
:
A
The equation for bond dissociation can be given by

C H_{4}

(g)

⟶

C(g) + 4H(g)

Δ

H = 397.8 kcal
There are in total of 4 C - H bonds
Therefore the energy needed to break a C - H bond can be given by

\frac{397.8}{4}

= + 99.45 kcal

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