Question
For the reaction H2O(s)⇋H2O(l) at 0°C and normal pressure
Answer: Option B
:
B
Let's look at the reaction.
H2O(s)⇋H2O(l) at 0∘C
It will be in equilibrium at 0∘C
Now, At equilibrium
△G = 0
&△G = △H - T△S
⇒△H - T△S = 0
⇒△H=T△S
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:
B
Let's look at the reaction.
H2O(s)⇋H2O(l) at 0∘C
It will be in equilibrium at 0∘C
Now, At equilibrium
△G = 0
&△G = △H - T△S
⇒△H - T△S = 0
⇒△H=T△S
Was this answer helpful ?
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