Question
tan2 θ(sec θ−1)2=
Answer: Option D
:
D
tan2θ(secθ−1)2=sec2θ−1(secθ−1)2
=(secθ−1)(secθ+1)(secθ−1)(secθ−1)
=1cosθ+11cosθ−1
=1+cosθcosθ1−cosθcosθ
=1+cosθ1−cosθ
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:
D
tan2θ(secθ−1)2=sec2θ−1(secθ−1)2
=(secθ−1)(secθ+1)(secθ−1)(secθ−1)
=1cosθ+11cosθ−1
=1+cosθcosθ1−cosθcosθ
=1+cosθ1−cosθ
Was this answer helpful ?
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