1 1 + t a n 2 θ + 1 1 + c o t 2 θ = Options: A . &nbsp-1 B . &nbsp0 C . &nbsp1 D . &nbsp2

Answer: Option C : C We know that, 1 + t a n 2 θ = s e c 2 θ and 1 + c o t 2 θ = c o s e c 2 θ 1 1 + t a n 2 θ + 1 1 + c o t 2 θ = 1 s e c 2 θ + 1 c o s e c 2 θ = c o s 2 θ + s i n 2 θ = 1

11+tan2θ+11+cot2θ=

Question

\frac{1}{1 + t a n^{2} θ} + \frac{1}{1 + c o t^{2} θ} =

Options:

A . -1

B . 0

C . 1

D . 2

Answer: Option C
:
C
We know that,

1 + t a n^{2} θ = s e c^{2} θ and 1 + c o t^{2} θ = c o s e c^{2} θ

\frac{1}{1 + t a n^{2} θ} + \frac{1}{1 + c o t^{2} θ} = \frac{1}{s e c^{2} θ} + \frac{1}{c o s e c^{2} θ}

= c o s^{2} θ + s i n^{2} θ

= 1

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