Question
sec 17∘cosec 73∘+tan 68∘cot 22∘−[cos2 44∘+cos2 46∘]=___.
Answer: Option D
:
D
sec17∘cosec73∘+tan68∘cot22∘−[cos244∘+cos246∘]
=sec17∘cosec(90∘−17∘)+tan68∘cot(90∘−68∘)−[cos244∘+cos2(90∘−44∘)]
=sec17∘sec17∘+tan68∘tan68∘−[cos244∘+sin244∘]....(complementary angles)
=1+1−1
=1
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:
D
sec17∘cosec73∘+tan68∘cot22∘−[cos244∘+cos246∘]
=sec17∘cosec(90∘−17∘)+tan68∘cot(90∘−68∘)−[cos244∘+cos2(90∘−44∘)]
=sec17∘sec17∘+tan68∘tan68∘−[cos244∘+sin244∘]....(complementary angles)
=1+1−1
=1
Was this answer helpful ?
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