Question
(1+tan A)2+(1−tan A)2=
Answer: Option C
:
C
⇒(1+tanA)2+(1−tanA)2
=(1+tan2A+2tanA)+(1+tan2A−2tanA)
=(2+2tan2A+2tanA−2tanA)
=(2+2tan2A)
=2(1+tan2A)
=2sec2A
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:
C
⇒(1+tanA)2+(1−tanA)2
=(1+tan2A+2tanA)+(1+tan2A−2tanA)
=(2+2tan2A+2tanA−2tanA)
=(2+2tan2A)
=2(1+tan2A)
=2sec2A
Was this answer helpful ?
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