Question
Solve for x if 4(2x+3)2−(2x+3)−14=0.
Answer: Option A
:
A
Given:4(2x+3)2−(2x+3)−14=0
Substitute (2x+3)=y, Hence the given equation reduces to
4y2−y−14=0
⇒ 4y2−8y+7y−14=0
⇒ 4y(y−2)+7(y−2)=0
⇒ (4y+7)(y−2)=0
⇒ y=−74ory=2
When y=−74,
(2x+3)=−74
2x=−194
⇒x=−198
When y=2,
(2x+3)=2
2x=−1
⇒x=−12
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:
A
Given:4(2x+3)2−(2x+3)−14=0
Substitute (2x+3)=y, Hence the given equation reduces to
4y2−y−14=0
⇒ 4y2−8y+7y−14=0
⇒ 4y(y−2)+7(y−2)=0
⇒ (4y+7)(y−2)=0
⇒ y=−74ory=2
When y=−74,
(2x+3)=−74
2x=−194
⇒x=−198
When y=2,
(2x+3)=2
2x=−1
⇒x=−12
Was this answer helpful ?
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