Question
Ram drew ∠ABC and then he drew a line segment BD such that the line segment BD is angle bisector of ∠ABC. Then, ∠(ABC)= __ ×∠(ABD).
Answer:
:
As stated in question line segment BD is angle bisector so, ∠ABD=∠DBC
And, ∠ABD+∠DBC=∠ABC
So,∠(ABC)=2∠(ABD)
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:
As stated in question line segment BD is angle bisector so, ∠ABD=∠DBC
And, ∠ABD+∠DBC=∠ABC
So,∠(ABC)=2∠(ABD)
Was this answer helpful ?
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