Construct ΔPQR, given ¯¯¯¯¯¯¯¯PQ=6.5 cm,¯¯¯¯¯¯¯¯PR=7 cm, and ¯¯¯¯¯¯¯¯¯QR=8 cm [3 MARKS]
Answer: : Construction: 2 Marks Steps: 1 Mark 1) Draw ¯¯¯¯¯¯¯¯PQ=6.5cm 2) With P as centre, draw an arc with radius equal to 7 cm. 3) With Q as centre, draw another arc with radius 8 cm to cut the previous arc at R. 4) Join R to P and Q. PQR is the required triangle.
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