Probability of a fraudster being caught is 1 2 and committing a fraud is 3 5 . What is his chance of not going to jail? Options: A . &nbsp70% B . &nbsp50% C . &nbsp40% D . &nbsp35%

Probability of a fraudster being caught is 12 and committing a fraud is 35. What

Question

Probability of a fraudster being caught is

\frac{1}{2}

and committing a fraud is

\frac{3}{5}

. What is his chance of not going to jail?

Options:

A . 70%

B . 50%

C . 40%

D . 35%

Answer: Option A
:
A
P(not going to jail)= P( F')+ P(F intersection C')
where P(F) is the probability of commiting a fraud and P(C) is the Probability of being caught
P(F')=

\frac{2}{5}

P(C')=

\frac{1}{2}

P(F intersection C')= P(F) ×P(C')=

\frac{3}{5} \times \frac{1}{2} = \frac{3}{10}

P(not going to jail)=

\frac{2}{5} + \frac{3}{10} = \frac{7}{10} = 70 %

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