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P,Q,R,S,T are points on a circle with centre O so that PTQ= 2 x RTS and PQ %undefined RS. Find SOQ, if P,O,Q are in a straight line


Options:
A .   45
B .   90
C .   60
D .   30
Answer: Option A
:
A

P,Q,R,S,T Are Points On A Circle With Centre O So That ∠PT...


PTQ= 90 (angle in a semi circle)


, hence RTS = 45.


ROS = 90 ( Inscribed angle= 2 *Angle at circumference)


OR=OS=OR (radius)


RSO = SOQ= 45 (interior alternate angles)


Option (a)



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