N= 4! + 5!+6!.........200!. Find the last two digits of N Options: A . &nbsp 00 B . &nbsp 13 C . &nbsp 04 D . &nbsp 54 E . &nbsp 24

N= 4! + 5!+6!.........200!. Find the last two digits of N

Question

N= 4! + 5!+6!.........200!. Find the last two digits of N

Answer: Option C
:
C

After 10!, the factorials end with 0 as the last two digits. We thusneed to find the last two digits from 4! To 9! Only

4!+5!+6!....9!= 24+120 + 720 + 5040 + 40320 + 362880 = ___04

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