Question
How many two digit odd numbers are there with 10 factors?
Answer: Option E
:
E
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:
E
10 factors implies that the number can be of the form
1) a9 ( Least odd number will be 39)
2) ab4 (Least odd number will be 34∗5=405)
Therefore, as the least number is 405, there are no two digit numbers of the specified form. The answer is 0.
If a number N can be factorized as N=am∗bn(a, b are the prime factors)
Then number of factors= (m+1)(n+1)
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