Question
limx→01−cos 3xx(3x−1)=
Answer: Option B
:
B
limx→01−cos3xx(3x−1)
cos3x=1−9x22!+…
1−cos3x=9x22!+… ......... (1)
limx→03x−1x=log3 .......... (2)
limx→01−cos3xx2(3x−1x)
From (1) and (2) we get
=92log3
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:
B
limx→01−cos3xx(3x−1)
cos3x=1−9x22!+…
1−cos3x=9x22!+… ......... (1)
limx→03x−1x=log3 .......... (2)
limx→01−cos3xx2(3x−1x)
From (1) and (2) we get
=92log3
Was this answer helpful ?
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