Question
Let A = { x : x ∈ R, |x| < 1}; B = {x : x ∈ R, |x-1| ≥ 1} and
A ∪ B = R - D, then the set D is
A ∪ B = R - D, then the set D is
Answer: Option B
:
B
A = {x:x∈ R, -1 < x < 1}
B = {x:x∈ R:x-1≤ -1 or x-1≥ 1}
= {x : x∈ R:x≤ 0 or x≥ 2}
∴ A∪ B = R - D, where D = {x : x∈ R, 1≤ x < 2}.
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B
A = {x:x∈ R, -1 < x < 1}
B = {x:x∈ R:x-1≤ -1 or x-1≥ 1}
= {x : x∈ R:x≤ 0 or x≥ 2}
∴ A∪ B = R - D, where D = {x : x∈ R, 1≤ x < 2}.
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