Question
Let n(U) = 700, n(A) = 200, n(B) = 300 and n(A ∩ B) = 100,
Then n(Ac∩Bc) =
Then n(Ac∩Bc) =
Answer: Option C
:
C
n(Ac∩Bc) = n(U) - n(A∪ B)
= n(U) - [n(A) + n(B) - n(A∩ B)]
= 700 - [200 + 300 - 100] = 300.
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:
C
n(Ac∩Bc) = n(U) - n(A∪ B)
= n(U) - [n(A) + n(B) - n(A∩ B)]
= 700 - [200 + 300 - 100] = 300.
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