The circumradius of a triangle with its vertices at (1, -2), (-3, 0) and (5, 6)

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Question

The circumradius of a triangle with its vertices at (1, -2), (-3, 0) and (5, 6) is

Options:

A . 5

B . 10

C . √5

D . √102

Answer: Option A
:
A
A(1, - 2) ,B(- 3, 0) and C(5, 6)
AB =

\sqrt{20}

, BC =

\sqrt{100}

, AC =

\sqrt{80}

B C^{2} = A B^{2} + A C^{2}

ABC is a right angled triangle with the right angle at A.
Circumradius is half the length of the hypotenuse.
R =

\frac{1}{2} \times

BC, BC = 5. Option(a).

The Circumradius Of A Triangle With Its Vertices At (1, -2),...

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