Question
Answer: Option D
:
D
iL=9030=3A, ic=9090=1A
Net current through circuit i=ic−iL=2A
∴Z=Vi=902=45Ω
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:
D
iL=9030=3A, ic=9090=1A
Net current through circuit i=ic−iL=2A
∴Z=Vi=902=45Ω
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