The instantaneous values of current and emf in an ac circuit are I = 1 √ 2 s i n 314tamp and E = √ 2 s i n ( 314 t − Π 6 ) V respectively. The phase difference between E and I will be Options: A . &nbsp−Π6rad B . &nbsp−Π3rad C . &nbspΠ6rad D . &nbspΠ3rad

The instantaneous values of current and emf in an ac circuit are I=1√2sin

Question

The instantaneous values of current and emf in an ac circuit are

I = \frac{1}{\sqrt{2}} s i n

314tamp and

E = \sqrt{2} s i n (314 t - \frac{Π}{6})

V respectively. The phase difference between E and I will be

Options:

A . −Π6rad

B . −Π3rad

C . Π6rad

D . Π3rad

Answer: Option A
:
A
Phase difference relative to the current

ϕ = (314 t - \frac{π}{6}) - (314 t) = - \frac{π}{6}

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