Question
The r.m.s. current in an ac circuit is 2 A. If the watt less current be √3 A , what is the power factor
Answer: Option D
:
D
iwL=irmssinϕ⇒√3=2sinϕ⇒sinϕ=√32
⇒ϕ=60∘ so p.f =cosϕ=cos60∘=12.
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:
D
iwL=irmssinϕ⇒√3=2sinϕ⇒sinϕ=√32
⇒ϕ=60∘ so p.f =cosϕ=cos60∘=12.
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