Question
In a triangle ABC, ∠A = 90°, ∠C = 55°, $${AD}$$ ⊥ $${BC}$$. What is the value of ∠BAD ?
Answer: Option D
According to question,
In right angle ΔBAC
∠A + ∠B + ∠C = 180°
∠B = 180° - 55° - 90°
∠B = 35°
In right angle ΔADB
∠ADB + ∠ABD + ∠BAD = 180°
∠BAD = 180° - 35° - 90°
∠BAD = 55°
Alternate
ΔBAC ∼ ΔBDA
∴ ∠BCA = ∠BAD = 55°
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According to question,
In right angle ΔBAC
∠A + ∠B + ∠C = 180°
∠B = 180° - 55° - 90°
∠B = 35°
In right angle ΔADB
∠ADB + ∠ABD + ∠BAD = 180°
∠BAD = 180° - 35° - 90°
∠BAD = 55°
Alternate
ΔBAC ∼ ΔBDA
∴ ∠BCA = ∠BAD = 55°
Was this answer helpful ?
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