Question
ABC is a right-angled triangle with AB = 6 cm and BC = 8 cm. A circle with center O has been inscribed inside ΔABC. The radius of the circle is
Answer: Option B
According to question,
Given :
AB = 6 cm, BC = 8 cm
In right angle ΔABC
By using Pythagoras theorem
AC2 = AB2 + BC2
AC2 = 62 + 82
AC2 = 36 + 64
AC2 = 100
AC = 10 cm
In radius
$$\eqalign{
& = \frac{{a + b - c}}{2} \cr
& = \frac{{8 + 6 - 10}}{2} \cr
& = \frac{4}{2} \cr
& = 2\,cm \cr} $$
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According to question,
Given :
AB = 6 cm, BC = 8 cm
In right angle ΔABC
By using Pythagoras theorem
AC2 = AB2 + BC2
AC2 = 62 + 82
AC2 = 36 + 64
AC2 = 100
AC = 10 cm
In radius
$$\eqalign{
& = \frac{{a + b - c}}{2} \cr
& = \frac{{8 + 6 - 10}}{2} \cr
& = \frac{4}{2} \cr
& = 2\,cm \cr} $$
Was this answer helpful ?
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