Question
If z is a complex number ¯¯¯¯¯¯¯¯z−1(¯z) = , then
Answer: Option A
:
A
Let z = x + iy, ¯z = x -iy and z−1=1x+iy
⇒¯¯¯¯¯¯¯¯z−1=x+iyx2+y2 ; ∴¯¯¯¯¯¯¯¯z−1¯z=x+iyx2+y2(x−iy) = 1
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:
A
Let z = x + iy, ¯z = x -iy and z−1=1x+iy
⇒¯¯¯¯¯¯¯¯z−1=x+iyx2+y2 ; ∴¯¯¯¯¯¯¯¯z−1¯z=x+iyx2+y2(x−iy) = 1
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