Question
If z is a complex number, then z.¯z = 0 if and only if
Answer: Option A
:
A
Let z = x+iy,¯z = x-iy
∴ z¯z = 0⇒ (x+iy)(x-iy) = 0 ⇒ x2+y2 = 0
It is possible onle when x and y oth simultaneously zero
i.e, z = 0 +0i = 0
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:
A
Let z = x+iy,¯z = x-iy
∴ z¯z = 0⇒ (x+iy)(x-iy) = 0 ⇒ x2+y2 = 0
It is possible onle when x and y oth simultaneously zero
i.e, z = 0 +0i = 0
Was this answer helpful ?
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