Question
If the (r+1)th term in the expansion of (3√a√b+√b3√a)21 has the same power of a and b, then value of r is
Answer: Option A
:
A
We have Tr+1 =21Cr(3√a√b)21−r(√b3√a)r
=21Cra7−(r2)b23r−(72)
Since the powers of a and b are the same,
therefore
7 - r2 = 23r - 72 ⇒ r = 9
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:
A
We have Tr+1 =21Cr(3√a√b)21−r(√b3√a)r
=21Cra7−(r2)b23r−(72)
Since the powers of a and b are the same,
therefore
7 - r2 = 23r - 72 ⇒ r = 9
Was this answer helpful ?
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